-5x^2-2x=0

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Solution for -5x^2-2x=0 equation: 



-5x^2-2x=0

a = -5; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-5)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-5}=\frac{0}{-10}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-5}=\frac{4}{-10}
=-2/5
$

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